This is a method of randomly sampling n items from a set of M items, with equal probability; where M >= n and M, the number of items is unknown until the end. This means that the equal probability sampling should be maintained for all successive items > n as they become available (although the content of successive samples can change).
- The algorithm
- Select the first n items as the sample as they become available;
- For the i-th item where i > n, have a random chance of n/i of keeping it. If failing this chance, the sample remains the same. If not, have it randomly (1/n) replace one of the previously selected n items of the sample.
- Repeat #2 for any subsequent items.
- The Task
- Create a function
s_of_n_creator
that given n the maximum sample size, returns a functions_of_n
that takes one parameter,item
. - Function
s_of_n
when called with successive items returns an equi-weighted random sample of up to n of its items so far, each time it is called, calculated using Knuths Algorithm S. - Test your functions by printing and showing the frequency of occurrences of the selected digits from 100,000 repetitions of:
-
- Use the s_of_n_creator with n == 3 to generate an s_of_n.
- call s_of_n with each of the digits 0 to 9 in order, keeping the returned three digits of its random sampling from its last call with argument item=9.
Note: A class taking n and generating a callable instance/function might also be used.
- Reference
- The Art of Computer Programming, Vol 2, 3.4.2 p.142
#include <iostream> #include <functional> #include <vector> #include <cstdlib> #include <ctime> template <typename T> std::function<std::vector<T>(T)> s_of_n_creator(int n) { std::vector<T> sample; int i = 0; return [=](T item) mutable { i++; if (i <= n) { sample.push_back(item); } else if (std::rand() % i < n) { sample[std::rand() % n] = item; } return sample; }; } int main() { std::srand(std::time(NULL)); int bin[10] = {0}; for (int trial = 0; trial < 100000; trial++) { auto s_of_n = s_of_n_creator<int>(3); std::vector<int> sample; for (int i = 0; i < 10; i++) sample = s_of_n(i); for (int s : sample) bin[s]++; } for (int x : bin) std::cout << x << std::endl; return 0; }
- Output:
30052 29740 30197 30223 29857 29688 30095 29803 30098 30247
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