C++: Mode


Write a program to find the mode value of a collection. The case where the collection is empty may be ignored. Care must be taken to handle the case where the mode is non-unique.

If it is not appropriate or possible to support a general collection, use a vector (array), if possible. If it is not appropriate or possible to support an unspecified value type, use integers.

#include <iterator>
#include <utility>
#include <algorithm>
#include <list>
#include <iostream>

// helper struct
template<typename T> struct referring
	referring(T const& t): value(t) {}
	template<typename Iter>
	bool operator()(std::pair<Iter, int> const& p) const
		return *p.first == value;
	T const& value;

// requires:
// FwdIterator is a ForwardIterator
// The value_type of FwdIterator is EqualityComparable
// OutIterator is an output iterator
// the value_type of FwdIterator is convertible to the value_type of OutIterator
// [first, last) is a valid range
// provides:
// the mode is written to result
template<typename FwdIterator, typename OutIterator>
void mode(FwdIterator first, FwdIterator last, OutIterator result)
	typedef typename std::iterator_traits<FwdIterator>::value_type value_type;
	typedef std::list<std::pair<FwdIterator, int> > count_type;
	typedef typename count_type::iterator count_iterator;

	// count elements
	count_type counts;

	while (first != last)
		count_iterator element = std::find_if(counts.begin(), counts.end(),
		if (element == counts.end())
		counts.push_back(std::make_pair(first, 1));

	// find maximum
	int max = 0;
	for (count_iterator i = counts.begin(); i != counts.end(); ++i)
	if (i->second > max)
	max = i->second;

	// copy corresponding elements to output sequence
	for (count_iterator i = counts.begin(); i != counts.end(); ++i)
	if (i->second == max)
	*result++ = *i->first;

// example usage
int main()
	int values[] = { 1, 2, 3, 1, 2, 4, 2, 5, 2, 3, 3, 1, 3, 6 };
	median(values, values + sizeof(values)/sizeof(int),
	std::ostream_iterator<int>(std::cout, " "));
	std::cout << std::endl;
	return 0;
2 3


Content is available under GNU Free Documentation License 1.2.

Our team found a curious site for our readers that are fans of online gaming, a rather exciting site that provides the latest gaming technology. Casinodots.com is the site, they compile the best reviews of MGA casino utan svensk licens sites. This site might pique your curiosity and you can win extra money!