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C++ Interview Question 17 Answer

Bjarne-stroustrup
 

Answer

This question is compilable and deterministic.

Its output is “B”.

Explanation

The “trick” here is that B::f() is called even though it is private.

As §11.5.2 in the standard puts it: “Access is checked at the call point using the type of the expression used to denote the object for which the member function is called”. The call point here being a.f(), and the type of the expression is A&.

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